# Midpoint of a Line Segment

- 1Use the formula below to find the midpoint between A(3,2) and B(5,8). $$\text{midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$$
- 2Use the formula below to find the midpoint between A(-3,2) and B(5,6). $$\text{midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$$
- 3Use the formula below to find the midpoint between A(-8,-3) and B(-2,-1). $$\text{midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$$
- 4A parallelogram has vertices A(-3,-2), B(2,3), C(6,4) and D(1,-1). Verify that the diagonals bisect each other.
- 5A parallelogram has vertices W(-1,3), X(-2,0), Y(4,-2) and Z(5,1). Verify that the diagonals bisect each other.
- 6For a line segment AB one end point is A(-2,6) and the midpoint is M(-1,-3). Find the coordinates of end point B.

Good test question ! - 7For a line segment AB one end point is A(-3,1) and the midpoint is M(-1,-3). Find the coordinates of end point B.
- 8The centre of a circle has coordinates (0,0). One endpoint of the diameter of the circle is (4,5). What are the coordinates of the other endpoint of the diameter?

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